如何得出,n趋向于正无穷大,lim((b^n)/(n!))=0,式中为b的n次方,b为常数?
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如何得出,n趋向于正无穷大,lim((b^n)/(n!))=0,式中为b的n次方,b为常数?
如何得出,n趋向于正无穷大,lim((b^n)/(n!))=0,式中为b的n次方,b为常数?
如何得出,n趋向于正无穷大,lim((b^n)/(n!))=0,式中为b的n次方,b为常数?
利用夹逼定理:
0
运用n次洛比达法则
limb^n/n!=limb^n-1/(n-1)!=...=limb/n=0(因为n趋向无穷大,b为常数)
如何得出,n趋向于正无穷大,lim((b^n)/(n!))=0,式中为b的n次方,b为常数?
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