(3)log(a)(M^n)=nlog(a)(M) (n∈R)能帮我解释一下吗?我没看懂 谢
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![(3)log(a)(M^n)=nlog(a)(M) (n∈R)能帮我解释一下吗?我没看懂 谢](/uploads/image/z/7263348-60-8.jpg?t=%EF%BC%883%EF%BC%89log%28a%29%28M%5En%29%3Dnlog%28a%29%28M%29+%EF%BC%88n%E2%88%88R%EF%BC%89%E8%83%BD%E5%B8%AE%E6%88%91%E8%A7%A3%E9%87%8A%E4%B8%80%E4%B8%8B%E5%90%97%3F%E6%88%91%E6%B2%A1%E7%9C%8B%E6%87%82+%E8%B0%A2)
(3)log(a)(M^n)=nlog(a)(M) (n∈R)能帮我解释一下吗?我没看懂 谢
(3)log(a)(M^n)=nlog(a)(M) (n∈R)能帮我解释一下吗?我没看懂 谢
(3)log(a)(M^n)=nlog(a)(M) (n∈R)能帮我解释一下吗?我没看懂 谢
根据对数的定义啊:log(a)(M),则可以设a^k=M;
由a^(kn)=a^k^n=M^n,可以知道,
log(a)(M^n)=log(a)(a^(kn))=kn=nlog(a)(M)
证明:log(a)(M^n)=nlog(a)(M)
log(a^n)(M)=1/nlog(a)(M)..
log(a)(M^n)=nlog(a)(M) 的推导log(a)(M^n)=nlog(a)(M)
log(a)(M^n)=nlog(a)(M) (n∈R) 则log(2)(3)^-3=? 底数为2,3的负三次方为多少?
证明对数运算法则(1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N);(1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N); (3)log(a)(M^n)=nlog(a)(M) (n∈R)
Nlog(a)(M)是否等于log^N(a)(M)
(3)log(a)(M^n)=nlog(a)(M) (n∈R)能帮我解释一下吗?我没看懂 谢
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