1/(1-√2)=?(化简结果及过程)

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1/(1-√2)=?(化简结果及过程)

1/(1-√2)=?(化简结果及过程)
1/(1-√2)=?(化简结果及过程)

1/(1-√2)=?(化简结果及过程)
1*(1+√2)/[(1-√2)*(1+√2)]
1+√2/(1-2)
-1-√2

1/(1-√2)
=1*(1+√2)/[(1-√2)(1+√2)]
=(1+√2)/[1²-(√2)²]
=(1+√2)/(1-2)
=-1-√2

=(1+√2)/(1-√2)(1+√2)
=(1+√2)/(1-2)
=-1-√2

1/(1-√2)=(1+√2)/(1-2)=-1-√2

=(1+√2)/(1-√2)(1+√2)
=(1+√2)/(1-2)
=-1-√2

1/(1-√2)
=(1+√2)/(1-√2)(1+√2)
=-(1+√2)
=-1-√2

1/(1-√2)
=1*(1+√2)/[(1-√2)(1+√2)]
=(1+√2)/[1²-(√2)²]
=(1+√2)/(1-2)
=-1-√2
嘿嘿~