作业帮一道微积分的数学题,谁来帮我解一下...（alevel进阶数学的）英语好的来..Solve the equation dy/dx=-g-kv given that v=u t=0,and that u,g,k are positive constant.Sketch the curve indicating the velocity which v approaches as t be
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/12 02:09:25
一道微积分的数学题,谁来帮我解一下...（alevel进阶数学的）英语好的来..Solve the equation dy/dx=-g-kv given that v=u t=0,and that u,g,k are positive constant.Sketch the curve indicating the velocity which v approaches as t be
一道微积分的数学题,谁来帮我解一下...（alevel进阶数学的）英语好的来..
Solve the equation dy/dx=-g-kv given that v=u t=0,and that u,g,k are positive constant.
Sketch the curve indicating the velocity which v approaches as t becomes large.
不用画图,帮我解一下那个方程就好>
一道微积分的数学题,谁来帮我解一下...（alevel进阶数学的）英语好的来..Solve the equation dy/dx=-g-kv given that v=u t=0,and that u,g,k are positive constant.Sketch the curve indicating the velocity which v approaches as t be
我怀疑你的方程错了,应该是dv/dt=-g-kv
这是物理上上抛运动加阻力的运动方程
如果你没打错,那我不会做了,后面的当废话.
dv/dt=-g-kv
dv/(-kv-g)=dt
∫dv/(-kv-g)=∫dt
-1/k*㏑(-kv-g)=t+C
㏑(-kv-g)=-kt+C
-kv=Ce^(-kt)+g
v=Ce^(-kt)-g/k
当t=0时v=u
代入u=C-g/k
C=u+g/k
v=(u+g/k)e^(-kt)-g/k
（C是待定常数,由初始条件决定,我默认C乘任意常数都用C来表示）
我英语不好。。如果你能把它翻成中文就好了。。
u,g,k都是常数？
而v=u，那v也是常数？
就是说-g-kv是常数？
即dy/dx=常数
那y=(-g-kv)x+C
M3？前面那个是dy／dx么，因为后面式子里没有出现x和y，奇怪的