若(x-y)的平方+丨5x-7y-2丨=0,则x= y=

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若(x-y)的平方+丨5x-7y-2丨=0,则x= y=

若(x-y)的平方+丨5x-7y-2丨=0,则x= y=
若(x-y)的平方+丨5x-7y-2丨=0,则x= y=

若(x-y)的平方+丨5x-7y-2丨=0,则x= y=
(x-y)的平方+丨5x-7y-2丨=0
(x-y)的平方=0,丨5x-7y-2丨=0
x=y,5x-7y-2=0
5x-7y-2=0
-2y=2
y=-1
所以x=y=-1

(x-y)的平方+丨5x-7y-2丨=0
x-y=0
5x-7y-2=0
x=-1
y=-1

x-y=0与5x-7y-2=0够成一个二元一次方程组,解出来即可,答案是x=-1,y=-1