作业帮请求高人帮我解一道英文数学题A sidewalk is to be constructed around a swimming pool that measures (10.0 ± 0.1) m by (17.0 ± 0.1) m.If the sidewalk is to measure (1.00 ± 0.01) m wide by (9.0 ± 0.1) cm thick,what volume of concrete is
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请求高人帮我解一道英文数学题A sidewalk is to be constructed around a swimming pool that measures (10.0 ± 0.1) m by (17.0 ± 0.1) m.If the sidewalk is to measure (1.00 ± 0.01) m wide by (9.0 ± 0.1) cm thick,what volume of concrete is
请求高人帮我解一道英文数学题
A sidewalk is to be constructed around a swimming pool that measures (10.0 ± 0.1) m by (17.0 ± 0.1) m.If the sidewalk is to measure (1.00 ± 0.01) m wide by (9.0 ± 0.1) cm thick,what volume of concrete is needed,and what is the approximate uncertainty of this volume?
请求高人帮我解一道英文数学题A sidewalk is to be constructed around a swimming pool that measures (10.0 ± 0.1) m by (17.0 ± 0.1) m.If the sidewalk is to measure (1.00 ± 0.01) m wide by (9.0 ± 0.1) cm thick,what volume of concrete is
【翻译】
一个游泳池周围要建人行道,游泳池的长宽是10.0（±0.1）米×17.0±（0.1 ）,米如果人行道是1.00 （± 0.01）米宽,9.0±（0.1）厘米厚.那么需要多少体积混凝土,有多少不确定度?
先来计算总体积：
V=[10.0×1.00×2+（17.0-2.0）×1.00×2]×0.090=4.5立方米
V(Max)=[10.1×1.01×2+（17.1-2.02）×1.01×2]×0.091=4.629立方米
V(Min)=[9.99×0.99×2+（16.9-1.98）×0.99×2]×0.089=4.374立方米
所以不确定度为+0.129和-0.126
用英文解答如下：
Sol：Volume of concrete=[10.0×1.00×2+（17.0-2.0）×1.00×2]×0.090=4.5m^3
V(Max)=[10.1×1.01×2+（17.1-2.02）×1.01×2]×0.091=4.629 m^3
V(Min)=[9.99×0.99×2+（16.9-1.98）×0.99×2]×0.089=4.374 m^3
Approximate uncertainty= ±0.13
先求所需体积：走道的长度是（10+17）*2,面积（10+17）*2*1,体积（10+17）*2*1*0.09=4.86立方米。
要求真高，会英语还要会数学
(9.0 ± 0.1) cm
变换成m得：(0.09 ± 0.001) m
标准使用水泥为：[10×1×2+17×1×2]×0.09≈4.9
最多使用水泥为：[10.1×1×2+17.1×1×2]×0.091≈5.0
最少使用水泥为：[9.9×1×2+16.9×1×2]×0.089≈4.8
所以使用水泥体积为（4.9±0.1）m³
等一下在给你画图解析呢！