求高人解英语数学题Truckco manufactures two types of trucks, types 1 and 2. Each truck must go through the painting shop and the assembly shop. If the painting shop were completely devoted to painting type 1 trucks, 800 per day could be paint

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求高人解英语数学题Truckco manufactures two types of trucks, types 1 and 2. Each truck must go through the painting shop and the assembly shop. If the painting shop were completely devoted to painting type 1 trucks, 800 per day could be paint

求高人解英语数学题Truckco manufactures two types of trucks, types 1 and 2. Each truck must go through the painting shop and the assembly shop. If the painting shop were completely devoted to painting type 1 trucks, 800 per day could be paint
求高人解英语数学题
Truckco manufactures two types of trucks, types 1 and 2. Each truck must go through the painting shop and the assembly shop. If the painting shop were completely devoted to painting type 1 trucks, 800 per day could be painted; whereas if the painting shop were completely devoted to painting type 2 trucks, 700 per day could be painted. If the assembly shop were completely devoted to assembling truck 1 engines, 1500 per day could be assembled, and if the assembly shop were completely devoted to assembling truck 2 engines, 1200 per day could be assembled. It is possible, however, to paint both types of trucks in the painting shop. Similarly, it is possible to assemble both types in the assembly shop. Each type 1 truck contributes $300 to profit; each type 2 truck contributes $500. According to the recent sales forecast, Truckco has to produce at least 200 type 1 trucks each day. The objective is to find a production plan that maximizes the daily profit. Formulate your model mathematically.

求高人解英语数学题Truckco manufactures two types of trucks, types 1 and 2. Each truck must go through the painting shop and the assembly shop. If the painting shop were completely devoted to painting type 1 trucks, 800 per day could be paint
题目的意思:Truckco公司制造两种卡车.然后要给他们刷油漆.第一种卡车,可以每天刷800辆,第二种700辆每天.然后组装厂可以装第一种1500辆每天,第二种1200辆每天.组装厂或者粉刷长每天都可以同时加工两种卡车.第一种卡车每辆有300美金利润,第二种有500美金每辆.第一种每天至少要做200辆.目标是算一个最大化利益的计划.

第一种x辆,第二种y辆
x>=200
x/800+y/700<=1
x/1500+y/1200<=1
从上面求出来
总利益公式.300x+500y
肯定是想尽量多生产第二辆扩大利益.要是不明确这点画个图就能看出来.
根据不等式,利益最大化是在1卡车200辆,2卡车525辆时,
所以最大利益是322500美金.
给我分吧.用了好久才回答的
^_^