作业帮求证arctan1+arctan2+arctan3=pai
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/10 14:22:53
求证arctan1+arctan2+arctan3=pai
求证arctan1+arctan2+arctan3=pai
求证arctan1+arctan2+arctan3=pai
证明:
设arctan1+arctan2+arctan3=x
那么tanx=tan(arctan1+arctan2+arctan3)
=(tan(arctan1+arctan2)+tan(arctan3))/(1-tan(arctan1+arctan2)tan(arctan3)
=(tan(arctan1+arctan2)+3)/(1-tan(arctan1+arctan2)*3)
又tan(arctan1+arctan2)=(tan(arctan1)+tan(arctan2))/(1-tan(arctan1)*tan(arctan2))=(1+2)/(1-2) =-3
所以tanx=(-3+3)/(1-(-3)*3)=0
而arctan1 arctan2 arctan3 都是锐角
故有x=π,即arctan1+arctan2+arctan3=π
求证arctan1+arctan2+arctan3=π.
求证arctan1+arctan2+arctan3=pai
arctan1+arctan2+arctan3=
arctan1+arctan2+arctan等于多少
求arctan1+arctan2+arctan3的值
arctan1+arctan2+arctan3=?不用计算器，
arctan1+arctan2+arctan3的计算过程?(不用计算器)
arctan3-arctan2=arctan1/7怎么算的啊
求证arctan1/2+arctan1/5+arctan1/8=pai/4
求函数值的题求arctan1+arctan2+arctan3的值
∫ x(arctan2/x - arctan1/x)dx这个定积分收敛性(从1积到正无穷)同上
求证恒等式：arctanX+arctan1/X=派/2
已知点A（-1,1),B(1,-1),点P是 直线Y=X-2上一点,求角APB最大时点P的坐标及角APB的 最大值怎么求得∠APBmax=arctan2-arctan1/2
arctan1/3+arctan1/2+arctan1=几,
arctan1/2+arctan1/5+arctan1/3
arctan1/3+arctan1/5+arctan1/7+arctan1/8如题
求值:arctan1/2+arctan1/3
arctan2＝?,sin（arctan2）＝?