main() {int k=1,s=0; do{if ((k%2)!=0) coutiune; s+=k;k++;}whlie(k>10); printf(%d",s);为什么whlie(k>10); 意思是K>10时才循环,
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![main() {int k=1,s=0; do{if ((k%2)!=0) coutiune; s+=k;k++;}whlie(k>10); printf(%d](/uploads/image/z/2445678-54-8.jpg?t=main%28%29+%7Bint+k%3D1%2Cs%3D0%3B+do%7Bif+%28%28k%252%29%21%3D0%29+coutiune%3B+s%2B%3Dk%3Bk%2B%2B%3B%7Dwhlie%28k%3E10%29%3B+printf%28%25d%22%2Cs%29%3B%E4%B8%BA%E4%BB%80%E4%B9%88whlie%28k%3E10%29%3B+%E6%84%8F%E6%80%9D%E6%98%AFK%3E10%E6%97%B6%E6%89%8D%E5%BE%AA%E7%8E%AF%2C)
main() {int k=1,s=0; do{if ((k%2)!=0) coutiune; s+=k;k++;}whlie(k>10); printf(%d",s);为什么whlie(k>10); 意思是K>10时才循环,
main() {int k=1,s=0; do{if ((k%2)!=0) coutiune; s+=k;k++;}whlie(k>10); printf(%d",s);
为什么whlie(k>10); 意思是K>10时才循环,
main() {int k=1,s=0; do{if ((k%2)!=0) coutiune; s+=k;k++;}whlie(k>10); printf(%d",s);为什么whlie(k>10); 意思是K>10时才循环,
每执行一次 就判断k的值,如果大于10,那么执行do里面的
main() {int j,k,p,s; s=0; for(j=1;j
c语言菜鸟 main() int s,k; for(s=1,k=2;k
int main(void) { int k=0; while(k++
#include main( ) { int k,sum=0 int count=0 for(k=1;k
main() {int k=1,s=0; do{if ((k%2)!=0) coutiune; s+=k;k++;}whlie(k>10); printf(%d,s);}结果多少?
#include Void main( ) {int k=1,s=0; do{if((k%2)!=0 continue; s+=k;k++; } while(k>0); pin
main() { char s[80]; int n=0,k=0; scanf(%s,s);while( );{if( )k=k+1,n++;}print(count-%d,k)}
main() {int k=0; while(printf(*)) {k++; if(k
fun(int k) {if(k>0)fun(k-1) printf(%d,k); } main() {int w=5; fun(w); }
void main() {int t=1;fun(fun(t));} fun(int h) {stvoid main(){int t=1;fun(fun(t));}fun(int h){static int a[3]={1,2,3}; int k; for(k=0;k
main() { int i=1,s=0; for(i
#include main() { int c=0,k; for (k=1;k
main() {int t=1;fun(fun(t));} fun(int h){static int a[3]={1,2,3};int k; for(k=0;k
为什么等于81#include main(){int s=0,i,j,k; for(i=1;i
main() {int k=1,s=0; do{if ((k%2)!=0) coutiune; s+=k;k++;}whlie(k>10); printf(%d,s);为什么whlie(k>10); 意思是K>10时才循环,
main(){int j,k,s,m;for( k=1 ; k < 10; k++ ){s=1; m= k+2;for( j=k; j
请看以下的程序填空main(){ int k,p;int s[]={1,-9,7,2,-10,3}for (p=0,k=p;ps[k]) __________printf(%d
,k);}`
void main( ) { char *s=12134211; int v[4]={0,0,0,0},k,i; for(k=0