solve the equation .solve the equation 2x³-3x²-11x+6=0 given that -2 is a zero of f(x)=2x³-3x²-11x+6.要翻译和解题过程

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solve the equation .solve the equation 2x³-3x²-11x+6=0 given that -2 is a zero of f(x)=2x³-3x²-11x+6.要翻译和解题过程

solve the equation .solve the equation 2x³-3x²-11x+6=0 given that -2 is a zero of f(x)=2x³-3x²-11x+6.要翻译和解题过程
solve the equation .
solve the equation 2x³-3x²-11x+6=0 given that -2 is a zero of f(x)=2x³-3x²-11x+6.
要翻译和解题过程

solve the equation .solve the equation 2x³-3x²-11x+6=0 given that -2 is a zero of f(x)=2x³-3x²-11x+6.要翻译和解题过程
我女朋友刚刚跟我说这是一元三次方程式,但她懒得算=( 而你的题目刚好是复古题,所以我在网路上帮你找到答案了
2x³ - 3x² - 11x + 6 = 0
First find a root by inspection:
P(x) = 2x³ - 3x² - 11x + 6
P(-2) = -16 -12 + 22 + 6 = 0 so (x + 2) is a factor of P(x)
Then after doing synthetic division:
2x² - 7x + 3 is found as a quadratic factor of P(x)
Factoring the quadratic:
(2x - 1)(x - 3)
So (x + 2)(2x - 1)(x - 3) = 0
x + 2 = 0 or 2x - 1 = 0 or x - 3 = 0
x = -2 or x = 1/2 or x = 3

已知:x=-2是 f(x)=2x³-3x²-11x+6的一个零点,求解方程: 2x³-3x²-11x+6=0。
由x=-2是 f(x)=2x³-3x²-11x+6的一个零点可知,(x+2)是2x³-3x²-11x+6的一个因式。
可以分解因式:2x³-3x²-11x+6=(x+2)X...

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已知:x=-2是 f(x)=2x³-3x²-11x+6的一个零点,求解方程: 2x³-3x²-11x+6=0。
由x=-2是 f(x)=2x³-3x²-11x+6的一个零点可知,(x+2)是2x³-3x²-11x+6的一个因式。
可以分解因式:2x³-3x²-11x+6=(x+2)X(2x-1)X(x-3)=0。
解得:x=-2,或0.5,或3。
祝学习进步哦~还有问题可以接着问我~分分给偶吧~

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