mathematica的表格的问题现有2个表格Table1和Table2,格式为table1=[{x1,y1},{x2,y2},{x3,y3},{x4,y4}],table2=[{x1,y5},{x2,y6},{x3,y7},{x4,y8}]如何求一个新表格table3,使得table3=[{x1,y5-y1},{x2,y5-y2},{x3,y7-y3},{x4,y8-y4}]就是说
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/22 01:10:56
![mathematica的表格的问题现有2个表格Table1和Table2,格式为table1=[{x1,y1},{x2,y2},{x3,y3},{x4,y4}],table2=[{x1,y5},{x2,y6},{x3,y7},{x4,y8}]如何求一个新表格table3,使得table3=[{x1,y5-y1},{x2,y5-y2},{x3,y7-y3},{x4,y8-y4}]就是说](/uploads/image/z/11505172-4-2.jpg?t=mathematica%E7%9A%84%E8%A1%A8%E6%A0%BC%E7%9A%84%E9%97%AE%E9%A2%98%E7%8E%B0%E6%9C%892%E4%B8%AA%E8%A1%A8%E6%A0%BCTable1%E5%92%8CTable2%2C%E6%A0%BC%E5%BC%8F%E4%B8%BAtable1%3D%5B%7Bx1%2Cy1%7D%2C%7Bx2%2Cy2%7D%2C%7Bx3%2Cy3%7D%2C%7Bx4%2Cy4%7D%5D%2Ctable2%3D%5B%7Bx1%2Cy5%7D%2C%7Bx2%2Cy6%7D%2C%7Bx3%2Cy7%7D%2C%7Bx4%2Cy8%7D%5D%E5%A6%82%E4%BD%95%E6%B1%82%E4%B8%80%E4%B8%AA%E6%96%B0%E8%A1%A8%E6%A0%BCtable3%2C%E4%BD%BF%E5%BE%97table3%3D%5B%7Bx1%2Cy5-y1%7D%2C%7Bx2%2Cy5-y2%7D%2C%7Bx3%2Cy7-y3%7D%2C%7Bx4%2Cy8-y4%7D%5D%E5%B0%B1%E6%98%AF%E8%AF%B4)
mathematica的表格的问题现有2个表格Table1和Table2,格式为table1=[{x1,y1},{x2,y2},{x3,y3},{x4,y4}],table2=[{x1,y5},{x2,y6},{x3,y7},{x4,y8}]如何求一个新表格table3,使得table3=[{x1,y5-y1},{x2,y5-y2},{x3,y7-y3},{x4,y8-y4}]就是说
mathematica的表格的问题
现有2个表格Table1和Table2,格式为table1=[{x1,y1},{x2,y2},{x3,y3},{x4,y4}],
table2=[{x1,y5},{x2,y6},{x3,y7},{x4,y8}]
如何求一个新表格table3,使得table3=[{x1,y5-y1},{x2,y5-y2},{x3,y7-y3},{x4,y8-y4}]
就是说前2个表格的x项都是相同的,只是y项不同,
现在的table3要求保留相同的x项,而使得y项为“table2的y项减去table1的相对应的y项”.
谢谢!
mathematica的表格的问题现有2个表格Table1和Table2,格式为table1=[{x1,y1},{x2,y2},{x3,y3},{x4,y4}],table2=[{x1,y5},{x2,y6},{x3,y7},{x4,y8}]如何求一个新表格table3,使得table3=[{x1,y5-y1},{x2,y5-y2},{x3,y7-y3},{x4,y8-y4}]就是说
table1 = {{x1,y1},{x2,y2},{x3,y3},{x4,y4}}
table2 = {{x1,y5},{x2,y6},{x3,y7},{x4,y8}}
table3 = Table[{table1[[i,1]],table2[[i,2]] - table1[[i,2]]},{i,1,4}]