1.找出下列方程满足条件的线,代入公式 Y=mx+b.( 原文:termine the euqation of the line that satisfies the following conditions.Write you answer in the slope-intercept form y=mx+b) 线十字交叉的通过 y=x^2-10x+3 和Y=
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![1.找出下列方程满足条件的线,代入公式 Y=mx+b.( 原文:termine the euqation of the line that satisfies the following conditions.Write you answer in the slope-intercept form y=mx+b) 线十字交叉的通过 y=x^2-10x+3 和Y=](/uploads/image/z/10899769-49-9.jpg?t=1.%E6%89%BE%E5%87%BA%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%E6%BB%A1%E8%B6%B3%E6%9D%A1%E4%BB%B6%E7%9A%84%E7%BA%BF%2C%E4%BB%A3%E5%85%A5%E5%85%AC%E5%BC%8F%E3%80%80Y%EF%BC%9Dmx%2Bb.%28+%E5%8E%9F%E6%96%87%EF%BC%9Atermine+the+euqation+of+the+line+that+satisfies+the+following+conditions.Write+you+answer+in+the+slope-intercept+form+y%3Dmx%2Bb%29%E3%80%80%E3%80%80%E7%BA%BF%E5%8D%81%E5%AD%97%E4%BA%A4%E5%8F%89%E7%9A%84%E9%80%9A%E8%BF%87+y%3Dx%5E2-10x%2B3+%E5%92%8CY%EF%BC%9D)
1.找出下列方程满足条件的线,代入公式 Y=mx+b.( 原文:termine the euqation of the line that satisfies the following conditions.Write you answer in the slope-intercept form y=mx+b) 线十字交叉的通过 y=x^2-10x+3 和Y=
1.找出下列方程满足条件的线,代入公式 Y=mx+b.( 原文:termine the euqation of the line that satisfies the following conditions.Write you answer in the slope-intercept form y=mx+b)
线十字交叉的通过 y=x^2-10x+3 和Y=-x^2-8x+7.(原文:It goes through the intersections if of y=x^2-10x+3 and y=-x^2-8x+7)
2.找出下列方程间的距离.(原文:Determine each of the following distances)
找出直线y=2x-1 和圆中心的x^2+y^2-4y=0 之间的距离!(Between the line y=2x-1 and the center of the circle x^2+y^2-4y=0)
修正:
Dtermine the euqation of the line that satisfies the following conditions.Write you answer in the slope-intercept form y=mx+b)
It goes through the intersections of y=x^2-10x+3 and y=-x^2-8x+7)
1.找出下列方程满足条件的线,代入公式 Y=mx+b.( 原文:termine the euqation of the line that satisfies the following conditions.Write you answer in the slope-intercept form y=mx+b) 线十字交叉的通过 y=x^2-10x+3 和Y=
交点坐标为(-1,14),(2,-13)
-m+b=14 2m+b=-13 联立解得:m=-9 b=5
求直线:y=-9x+5
2题x^2+y^2-4y=0
式子可化为 x^2+(y-2)^2=4
所以圆心O(0,2)半径r=2,过O作直线垂线交于A
设OA方程为y=-2x+b,代入O点,b=2.y=-2x+2
求出交点A坐标(3/4,1/2)
OA=(3根号11)/4
1. 联立解得:交点坐标为:(-1, 14),(2,-13)
-m+b=14 2m+b=-13 联立解得:m=-9 b=5
∴所求直线:y=-9x+5
2.x^2+y^2-4y=0
x^2+(y-2)^2=4
圆心坐标:(0,2)
直线方程:2x-y-1=0
圆心到直线的...
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1. 联立解得:交点坐标为:(-1, 14),(2,-13)
-m+b=14 2m+b=-13 联立解得:m=-9 b=5
∴所求直线:y=-9x+5
2.x^2+y^2-4y=0
x^2+(y-2)^2=4
圆心坐标:(0,2)
直线方程:2x-y-1=0
圆心到直线的距离=1/√5|-2-1|=3√5/5
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