X=3z X+y+z=12 X+2y-2z=10
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X=3z X+y+z=12 X+2y-2z=10
X=3z X+y+z=12 X+2y-2z=10
X=3z X+y+z=12 X+2y-2z=10
将1式代入2、3式得:y+4z=12,2y+z=10;y+4z=12方程两边乘以2后和2y+z=10相减得,7z=14,得z=2,将z=2代入,x=3z得x=6,将x=6,z=2代入x+y+z=12得,y=4,即方程组的解为x=6,y=4,z=2
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X=3z X+y+z=12 X+2y-2z=10
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