抛物线y=ax05+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6抛物线y=ax²+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6(1)求点B的坐标(2)求抛物线的解析式及顶点坐标(3
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![抛物线y=ax05+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6抛物线y=ax²+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6(1)求点B的坐标(2)求抛物线的解析式及顶点坐标(3](/uploads/image/z/10159521-33-1.jpg?t=%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dax05%2Bbx%2Bc%E4%B8%8Ey%E8%BD%B4%E4%BA%A4%E4%BA%8E%E7%82%B9C%2C%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%BA%8EA%E3%80%81B%E4%B8%A4%E7%82%B9%2Ctan%E8%A7%92OCA%3D1%2F3%2CS%E2%96%B3ABC%3D6%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dax%26%23178%3B%2Bbx%2Bc%E4%B8%8Ey%E8%BD%B4%E4%BA%A4%E4%BA%8E%E7%82%B9C%2C%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%BA%8EA%E3%80%81B%E4%B8%A4%E7%82%B9%2Ctan%E8%A7%92OCA%3D1%2F3%2CS%E2%96%B3ABC%3D6%EF%BC%881%EF%BC%89%E6%B1%82%E7%82%B9B%E7%9A%84%E5%9D%90%E6%A0%87%EF%BC%882%EF%BC%89%E6%B1%82%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%8F%8A%E9%A1%B6%E7%82%B9%E5%9D%90%E6%A0%87%EF%BC%883)
抛物线y=ax05+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6抛物线y=ax²+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6(1)求点B的坐标(2)求抛物线的解析式及顶点坐标(3
抛物线y=ax05+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6
抛物线y=ax²+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6
(1)求点B的坐标
(2)求抛物线的解析式及顶点坐标
(3)设点E在x轴上,点F在抛物线上,如果A、C、E、F构成平行四边形,请写出E的坐标
速度的给多50分
抛物线y=ax05+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6抛物线y=ax²+bx+c与y轴交于点C,与x轴交于A、B两点,tan角OCA=1/3,S△ABC=6(1)求点B的坐标(2)求抛物线的解析式及顶点坐标(3
E(-1,0),(3,0),(-2-√7,0),(-2+√7,0)
1.A既在直线上有在曲线上,代入直线方程,得A点纵坐标为2,把A(4,2)代入曲线方程,得K=8
2.A(4,2),B(-4,-2)P(x,8/x),Q(-x,-8/x)
AB=4√5,AB直线为y=1/2x,由P点到直线AB 的距离*4√5=24
得,|x-16/x|=6,解,X=8,-8,2,-2,
∵P在第一象限,负值舍,
P(8,1)或P(2,4)你...
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1.A既在直线上有在曲线上,代入直线方程,得A点纵坐标为2,把A(4,2)代入曲线方程,得K=8
2.A(4,2),B(-4,-2)P(x,8/x),Q(-x,-8/x)
AB=4√5,AB直线为y=1/2x,由P点到直线AB 的距离*4√5=24
得,|x-16/x|=6,解,X=8,-8,2,-2,
∵P在第一象限,负值舍,
P(8,1)或P(2,4)
收起
A点纵坐标为2,把A(4,2)代入曲线方程,得K=8
2.A(4,2),B(-4,-2)P(x,8/x),Q(-x,-8/x)
AB=4√5,AB直线为y=1/2x,由P点到直线AB 的距离*4√5=24
得,|x-16/x|=6,解,X=8,-8,2,-2,
∵P在第一象限,负值舍,
P(8,1)或P(2,4)