一道关于概率的SAT2数学题Of all the articles in a box, 80% are satisfactory, while 20% are not. The probability of obtaining exactly five good items out of eight randomly selected articles isA 0.003B 0.013C 0.132D 0.147E 0.800答案是C,但

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一道关于概率的SAT2数学题Of all the articles in a box, 80% are satisfactory, while 20% are not. The probability of obtaining exactly five good items out of eight randomly selected articles isA 0.003B 0.013C 0.132D 0.147E 0.800答案是C,但

一道关于概率的SAT2数学题Of all the articles in a box, 80% are satisfactory, while 20% are not. The probability of obtaining exactly five good items out of eight randomly selected articles isA 0.003B 0.013C 0.132D 0.147E 0.800答案是C,但
一道关于概率的SAT2数学题
Of all the articles in a box, 80% are satisfactory, while 20% are not. The probability of obtaining exactly five good items out of eight randomly selected articles is
A 0.003
B 0.013
C 0.132
D 0.147
E 0.800
答案是C,但是我有点疑问.
首先是对题目,这个eight randomly selected articles 应该不是只能有5个真品吧,应该还可以有6、7、8个真品吧?但按照Barron的解释,貌似只能有5个真品.为什么?
然后是对解题过程,为什么要乘C(8) 5? 乘这个是什么意思?
啊,不好意思~答案是D,可以解释一下吗?
为什么要乘C(8) 5?这个有什么含义?

一道关于概率的SAT2数学题Of all the articles in a box, 80% are satisfactory, while 20% are not. The probability of obtaining exactly five good items out of eight randomly selected articles isA 0.003B 0.013C 0.132D 0.147E 0.800答案是C,但
这个题目就是一个随机二项分布题目.
一个盒子里,正品的概率是0.8,次品的概率是0.2.
问你从箱子里取出8个物品,恰有5个正品.这个事件的概率是多少.
C(8,5)就是从8个物品中,任意选出5个物品的各种组合总数.不考虑各个物品的前后排列关系,明白么?如果是A(8,5),那就是考虑各个物品的前后关系.这里是随机抽取,不需要考虑各个物品的前后排列对应关系.
求出了各种组合数,就需要乘以各个事件相应的概率.一共有8个事件,3个事件是次品,5个事件是正品,次品发生概率是0.2,正品发生的概率是0.8.很简单:0.2^3*0.8^5.
这个事件的概率就是C(8,5)*0.2^3*0.8^5.
结果是D.