Given that f(x)=2x^2-12x+11, for the domain x>=0, find the range of f?

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Given that f(x)=2x^2-12x+11, for the domain x>=0, find the range of f?
Given that f(x)=2x^2-12x+11, for the domain x>=0, find the range of f?

Given that f(x)=2x^2-12x+11, for the domain x>=0, find the range of f?
求f(x)的值域
f(x)=2x^2-12x+11
f(x)=2[(x-3)^2]-7
x≥0
根据图像得
f(x)有最小值-7
所以f(x)∈[-7,+∞)
the range of f

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