(x^4+x^2+3)/(x^2+1)dx

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/27 03:49:18
(x^4+x^2+3)/(x^2+1)dx
(x%2)?("*%d"):("#%d");

(x%2)?("*%d"):("#%d");(x%2)?("*%d"):("#%d");(x%2)?("*%d"):("#%d");这是三元运算符?:,如果x%2!=0,则为真,结果就是*%d,若为假,即x%2==0,则值为#%d

设随机变量x的方差d(x)=3,则d(2x-1)=

设随机变量x的方差d(x)=3,则d(2x-1)=设随机变量x的方差d(x)=3,则d(2x-1)=设随机变量x的方差d(x)=3,则d(2x-1)=d(2x-1)=4d(X)=12

x^7次方等于()A.(-x^2)·x^5B.(-x^2)·x^5C.(-x^3)·x^4D.(-x

x^7次方等于()A.(-x^2)·x^5B.(-x^2)·x^5C.(-x^3)·x^4D.(-x)·(-x)^6x^7次方等于()A.(-x^2)·x^5B.(-x^2)·x^5C.(-x^3)·x^4D.(-x)·(-x)^6x^7次

若定积分∫f(x)[(x^3 sin^2( x))d(x)/x^4+2x^2+1] [上限为5下限为

若定积分∫f(x)[(x^3sin^2(x))d(x)/x^4+2x^2+1][上限为5下限为-5],∫[(x^3sin^2(x))d(x)/x^4+2x^2+1][上限为5下限为-5]若定积分∫f(x)[(x^3sin^2(x))d(x)

(x-1)^3(x+1)(x-2)/(x+4)

(x-1)^3(x+1)(x-2)/(x+4)(x-1)^3(x+1)(x-2)/(x+4)(x-1)^3(x+1)(x-2)/(x+4)(x-1)^3(x+1)(x-2)/(x+4)这不就是分子和分母异号嘛所以分子分母乘积也异号也即积<0

(x-3/x^2+3x+2)*(x^2/x^2-4x+3),(x^2-1/x-1÷x^2-x/x^2

(x-3/x^2+3x+2)*(x^2/x^2-4x+3),(x^2-1/x-1÷x^2-x/x^2-2x+1)这两道题怎么算(x-3/x^2+3x+2)*(x^2/x^2-4x+3),(x^2-1/x-1÷x^2-x/x^2-2x+1)这

(x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25

(x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25(x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25(x+1)(x+2)(x+3)(x+4)+1(x+1)(x-

计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1

计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1分子因式分解

1/(x+1)(x+2) + 1/(x+2)(x+3) + 1/(x+3)(x+4) + ...+

1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...+1/(x+2005)(x+2006)=1/2x+40121/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...+1/(x+2

(-x)1(-x)2(-x)3(-x^4)等于多少(-x)¹ * (-x)² *

(-x)1(-x)2(-x)3(-x^4)等于多少(-x)¹*(-x)²*(-x)³*(-x^4)=?太让我为难了真是的,怎么感觉谁都想采纳呢(-x)1(-x)2(-x)3(-x^4)等于多少(-x)¹

已知(6x^3+10x)/(x^4+x^2+1)=(ax+b)/(x^2+x+1)+(cx+d)/(

已知(6x^3+10x)/(x^4+x^2+1)=(ax+b)/(x^2+x+1)+(cx+d)/(x^2-x+1)求a+b+c+d的值已知(6x^3+10x)/(x^4+x^2+1)=(ax+b)/(x^2+x+1)+(cx+d)/(x^

已知(6x^3+10x)/(x^4+x^2+1)=(ax+b)/(x^2+x+1)+(cx+d)/(

已知(6x^3+10x)/(x^4+x^2+1)=(ax+b)/(x^2+x+1)+(cx+d)/(x^2-x+1)求a,b,c,d的值已知(6x^3+10x)/(x^4+x^2+1)=(ax+b)/(x^2+x+1)+(cx+d)/(x^

x^4表示( ) A.4x B.x+x+x+x c.x*x*x*x D.x+4

x^4表示()A.4xB.x+x+x+xc.x*x*x*xD.x+4x^4表示()A.4xB.x+x+x+xc.x*x*x*xD.x+4x^4表示()A.4xB.x+x+x+xc.x*x*x*xD.x+4BCx*x*x*xaCX的四次方Cx

请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360

请问这道题咋做:(x)X(x+1)X(x+2)X(x+3)=360请问这道题咋做:(x)X(x+1)X(x+2)X(x+3)=360请问这道题咋做:(x)X(x+1)X(x+2)X(x+3)=360x(x+3)(x+1)(x+2)=360(

x+5/x+1-3x-3/x+5=8x+28/x^2+4X-5-2(x+5)/(x+1)-(3x-3

x+5/x+1-3x-3/x+5=8x+28/x^2+4X-5-2(x+5)/(x+1)-(3x-3)/(x+5)=(8x+28)/(x^2+4X-5)-2x+5/x+1-3x-3/x+5=8x+28/x^2+4X-5-2(x+5)/(x+

(X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2

(X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0(X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0(X-3分之x-1-x分之x

^代表幂a,b,c,d都是正整数,请证明x^4a+x^(4b+1)+x^(4c+2)+x^(4d+3

^代表幂a,b,c,d都是正整数,请证明x^4a+x^(4b+1)+x^(4c+2)+x^(4d+3)能被x^3+x^2+x+1整除1楼的回答没有同时证明在同一个条件可以同时整除x+1和x^2+1你只是分两个不同条件分别可以证明而已。而^代

3x/(x-2)-x/(x+2)÷2x/(x-4)化简3x/(x-2)-x/(x+2)÷2x/(x&

3x/(x-2)-x/(x+2)÷2x/(x-4)化简3x/(x-2)-x/(x+2)÷2x/(x²-4)化简3x/(x-2)-x/(x+2)÷2x/(x-4)化简3x/(x-2)-x/(x+2)÷2x/(x²-4)化简

x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算

x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算=(x+1)(x-1)/(x+

[(2x+6)/(x^2-4x+4)]×[(x-2)/(x^2+3x)]-1/x-2化简!

[(2x+6)/(x^2-4x+4)]×[(x-2)/(x^2+3x)]-1/x-2化简![(2x+6)/(x^2-4x+4)]×[(x-2)/(x^2+3x)]-1/x-2化简![(2x+6)/(x^2-4x+4)]×[(x-2)/(x^