复数(1+i)² / 1﹣i 等于
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复数(1+i)² / 1﹣i 等于
复数(1+i)² / 1﹣i 等于
复数(1+i)² / 1﹣i 等于
(1+i)² / 1﹣i
=(1-1+2i)/(1-i)
=2i/(1-i)
=2i(1+i)/(1-i)(1+i)
=2i(1+i)/(1+1)
=i(1+i)
=i-1
(1+i)² / 1﹣i=(1+i)^3/(1+i)(1-i)=[(1+i)^3]/2
(1+i)² / 1﹣i
=2i/(1-i)
=2i(1+i)/(1-i)(1+i)
=2i(1+i)/2
=i(1+i)
=-1+i