当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²b )-2(2ab ²-a²b )
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当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²b )-2(2ab ²-a²b )
当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²b )-2(2ab ²-a²b )
当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²b )-2(2ab ²-a²b )
由题意可得:a-1=0,b+3=0
解得:a=1,b=-3
原式=-a^2b+3ab^2-a^2b-4ab^2+2a^2b
=(-1-1+2)a^2b+(3-4)ab^2
=-ab^2
=-1*(-3)^2
=-9