求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
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![求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)](/uploads/image/z/7631939-11-9.jpg?t=%E6%B1%82%E5%80%BCsin10%CF%80%2F3-%E6%A0%B9%E5%8F%B72cos%28-19%CF%80%2F4%29%2Btan%2813%CF%80%2F3%29)
求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
sin10π/3-根号2cos(-19π/4)+tan(13π/3)
=-sinπ/3-√2cos(3π/4)+tan(π/3)
=-√3/2+1+√3
=1-(√3/2)