因式分解(x^2+xy+y^6)^2-4xy(x^2+y^2)RT还有1t,向x^4+2001X^2+2000x+2001

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因式分解(x^2+xy+y^6)^2-4xy(x^2+y^2)RT还有1t,向x^4+2001X^2+2000x+2001

因式分解(x^2+xy+y^6)^2-4xy(x^2+y^2)RT还有1t,向x^4+2001X^2+2000x+2001
因式分解(x^2+xy+y^6)^2-4xy(x^2+y^2)
RT
还有1t,向x^4+2001X^2+2000x+2001

因式分解(x^2+xy+y^6)^2-4xy(x^2+y^2)RT还有1t,向x^4+2001X^2+2000x+2001
(x^2+xy+y^2)^2-4xy(x^2+y^2)
=[(x^2+y^2)+xy]^2-4xy(x^2+y^2)
=(x^2+y^2)^2+2xy(x^2+y^2)+(xy)^2-4xy(x^2+y^2)
=(x^2+y^2)^2-2xy(x^2+y^2)+(xy)^2
=(x^2+y^2-xy)^2
x^4+2001X^2+2000x+2001
将原式+X-X,构成
X^4+2001X^2+2000X+2001
=X^4-X+2001X^2+2001X+2001
=X(X^3-1)+2001(X^2+X+1)
=X(X-1)(X^2+X+1)+2001(X^2+X+1)
=(X^2+X+1)(X^2-X+2001)

是这个吗?
:(x^2+xy+y^2)^2-4xy(x^2+y^2)
(x^2+xy+y^2)^2-4xy(x^2+y^2)
=[(x^2+y^2)+xy]^2-4xy(x^2+y^2)
=(x^2+y^2)^2+2xy(x^2+y^2)+(xy)^2-4xy(x^2+y^2)
=(x^2+y^2)^2-2xy(x^2+y^2)+(xy)^2
=(x^2+y^2-xy)^2