作业帮arcsin[sin(19Π/12)]求值Π为3.1415926
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![arcsin[sin(19Π/12)]求值Π为3.1415926](/uploads/image/z/7014804-60-4.jpg?t=arcsin%5Bsin%2819%CE%A0%2F12%29%5D%E6%B1%82%E5%80%BC%CE%A0%E4%B8%BA3.1415926)
arcsin[sin(19Π/12)]求值Π为3.1415926
arcsin[sin(19Π/12)]求值
Π为3.1415926
arcsin[sin(19Π/12)]求值Π为3.1415926
y=arcsin(x),定义域[-1,1] ,值域[-π/2,π/2]
arcsin[sin(19Π/12)]=arcsin[sin(2π - 5π/12)]=arcsin[sin(-5π/12)]= -5π/12
arcsinx x属于[-π/2,π/2]
sin(19π/12)=sin(19π/12-2π)=sin(-5/12π)
所以arcsin[sin(19Π/12)]=-5/12π
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