已知抛物线y=ax²+bx+c的所示,(1)判断a,b,c及b²-4ac,a-b+c的符号,已知抛物线y=ax²+bx+c的所示, (1)判断a,b,c及b²-4ac,a-b+c的符号, (2)求a+b+c的值 (3)下列结论:①b<1,②b<2a,③a>1/
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 19:25:45
![已知抛物线y=ax²+bx+c的所示,(1)判断a,b,c及b²-4ac,a-b+c的符号,已知抛物线y=ax²+bx+c的所示, (1)判断a,b,c及b²-4ac,a-b+c的符号, (2)求a+b+c的值 (3)下列结论:①b<1,②b<2a,③a>1/](/uploads/image/z/6969517-61-7.jpg?t=%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dax%26%23178%3B%2Bbx%2Bc%E7%9A%84%E6%89%80%E7%A4%BA%2C%EF%BC%881%EF%BC%89%E5%88%A4%E6%96%ADa%2Cb%2Cc%E5%8F%8Ab%26%23178%3B-4ac%2Ca-b%2Bc%E7%9A%84%E7%AC%A6%E5%8F%B7%2C%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dax%26%23178%3B%2Bbx%2Bc%E7%9A%84%E6%89%80%E7%A4%BA%2C+%EF%BC%881%EF%BC%89%E5%88%A4%E6%96%ADa%2Cb%2Cc%E5%8F%8Ab%26%23178%3B-4ac%2Ca-b%2Bc%E7%9A%84%E7%AC%A6%E5%8F%B7%2C+%EF%BC%882%EF%BC%89%E6%B1%82a%2Bb%2Bc%E7%9A%84%E5%80%BC+%EF%BC%883%EF%BC%89%E4%B8%8B%E5%88%97%E7%BB%93%E8%AE%BA%EF%BC%9A%E2%91%A0b%EF%BC%9C1%2C%E2%91%A1b%EF%BC%9C2a%2C%E2%91%A2a%EF%BC%9E1%2F)
已知抛物线y=ax²+bx+c的所示,(1)判断a,b,c及b²-4ac,a-b+c的符号,已知抛物线y=ax²+bx+c的所示, (1)判断a,b,c及b²-4ac,a-b+c的符号, (2)求a+b+c的值 (3)下列结论:①b<1,②b<2a,③a>1/
已知抛物线y=ax²+bx+c的所示,(1)判断a,b,c及b²-4ac,a-b+c的符号,
已知抛物线y=ax²+bx+c的所示, (1)判断a,b,c及b²-4ac,a-b+c的符号, (2)求a+b+c的值 (3)下列结论:①b<1,②b<2a,③a>1/2,④a+c<1,⑤-a-b+c<0.其中正确的有_____,请说明理由.
已知抛物线y=ax²+bx+c的所示,(1)判断a,b,c及b²-4ac,a-b+c的符号,已知抛物线y=ax²+bx+c的所示, (1)判断a,b,c及b²-4ac,a-b+c的符号, (2)求a+b+c的值 (3)下列结论:①b<1,②b<2a,③a>1/
(1)∵抛物线开口向上,
∴a>0,
∵对称轴在y轴右侧,
∴b<0;
∵抛物线与y轴负半轴相交,
∴c<0,
∵抛物线与x轴交于两点,
∴b2-4ac>0,
∵x=-1时,y<0,
∴a-b+c<0;
(2)由函数的图象可知当x=1时,y=-3,
所以a+b+c=-3;