已知函数f(x)=1-2a-2acosx-2sin^2x的最小值为g(a),a∈R (1)求g(a),(2)若g(a)=1/2,求此时f(x)的最大值
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![已知函数f(x)=1-2a-2acosx-2sin^2x的最小值为g(a),a∈R (1)求g(a),(2)若g(a)=1/2,求此时f(x)的最大值](/uploads/image/z/638428-4-8.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D1-2a-2acosx-2sin%5E2x%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BAg%28a%29%2Ca%E2%88%88R+%EF%BC%881%EF%BC%89%E6%B1%82g%28a%29%2C%EF%BC%882%EF%BC%89%E8%8B%A5g%28a%29%3D1%2F2%2C%E6%B1%82%E6%AD%A4%E6%97%B6f%28x%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC)
已知函数f(x)=1-2a-2acosx-2sin^2x的最小值为g(a),a∈R (1)求g(a),(2)若g(a)=1/2,求此时f(x)的最大值
已知函数f(x)=1-2a-2acosx-2sin^2x的最小值为g(a),a∈R (1)求g(a),(2)若g(a)=1/2,求此时f(x)的最大值
已知函数f(x)=1-2a-2acosx-2sin^2x的最小值为g(a),a∈R (1)求g(a),(2)若g(a)=1/2,求此时f(x)的最大值
f(x)=1-2a-2acosx-2sin^2x
f(x)=1-2a-2acosx-2sin^2x
=1-2a-2acosx-2(1-cos^2x)
=1-2a-2acosx-2+2cos^2x
=2cos^2x-2acosx-2a-1
=2(cos^2x-acosx)-2a-1
=2(cos^2x-acosx+a^2/4)-a^2/2-2a-1
=2(cosx-a/2)^2-a^2/2-2a-1
当cosx-a/2=0时,f(x)的值最小(-2
f(x)=1-2a-2acosx-2sin^2x
f(x)=1-2a-2acosx-2sin^2x
=1-2a-2acosx-2(1-cos^2x)
=1-2a-2acosx-2+2cos^2x
=2cos^2x-2acosx-2a-1
=2(cos^2x-acosx)-2a-1
=2(cos^2x-acosx+a^2/4)-a^2/2-2...
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f(x)=1-2a-2acosx-2sin^2x
f(x)=1-2a-2acosx-2sin^2x
=1-2a-2acosx-2(1-cos^2x)
=1-2a-2acosx-2+2cos^2x
=2cos^2x-2acosx-2a-1
=2(cos^2x-acosx)-2a-1
=2(cos^2x-acosx+a^2/4)-a^2/2-2a-1
=2(cosx-a/2)^2-a^2/2-2a-1
当cosx-a/2=0时,f(x)的值最小(-2<=a<=2)
g(a)=-a^2/2-2a-1
-a^2/2-2a-1=1/2
a^2/2+2a+3/2=0
a^2+4a+3=0
(a+3)(a+1)=0
a=-1或a=-3(舍去)
f(x)=2(cosx-a/2)^2-a^2/2-2a-1
=2(cosx+1/2)^2-1/2+2-1
=2(cosx+1/2)^2+1/2
当cosx=1时,f(x)的值最大
f(x)=2(cosx+1/2)^2+1/2
=2(1+1/2)^2+1/2
=2*9/4+1/2
=9/2+1/2
=5
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