x,y满足x^2+2y^2-2xy-2y+1=0 求x乘以y的值

x,y满足x^2+2y^2-2xy-2y+1=0 求x乘以y的值
x,y满足x^2+2y^2-2xy-2y+1=0 求x乘以y的值

x,y满足x^2+2y^2-2xy-2y+1=0 求x乘以y的值
即(x²-2xy+y²)+(y²-2y+1)=0
(x-y)²+(y-1)²=0
所以x-y=y-1=0
所以x=y=1
所以xy=1