已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/19 10:34:36
![已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为](/uploads/image/z/571788-36-8.jpg?t=%E5%B7%B2%E7%9F%A5x%5E2-3x%2B1%3D0%2C%E5%88%99%E5%88%86%E5%BC%8Fx%5E2%2F%EF%BC%88x%5E4%2B4x%5E2%2B1%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%BA)
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
x^2-3x+1=0
x^2+1=3x
x^2/(x^4+4x^2+1)
=x^2/(x^2+1)^2
=x^2/9x^2
=1/9