已知数列an满足a1=a+2,an+1=根号2分之an+a,若a=0,求通项公式
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![已知数列an满足a1=a+2,an+1=根号2分之an+a,若a=0,求通项公式](/uploads/image/z/5433009-33-9.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97an%E6%BB%A1%E8%B6%B3a1%3Da%2B2%2Can%2B1%3D%E6%A0%B9%E5%8F%B72%E5%88%86%E4%B9%8Ban%2Ba%2C%E8%8B%A5a%3D0%2C%E6%B1%82%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F)
已知数列an满足a1=a+2,an+1=根号2分之an+a,若a=0,求通项公式
已知数列an满足a1=a+2,an+1=根号2分之an+a,若a=0,求通项公式
已知数列an满足a1=a+2,an+1=根号2分之an+a,若a=0,求通项公式
a1= a+2
a(n+1)=(an+a)/√2
if a=0
a1= 2
a(n+1)=an/√2
a(n+1)/an = 2^(-1/2)
an/a1 = 2^[-(n-1)/2]
an = 2^[(3-n)/2]
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