角α的终边经过点P(x,-√2)且cosα=(√3/6)x则sinα+tanα=
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![角α的终边经过点P(x,-√2)且cosα=(√3/6)x则sinα+tanα=](/uploads/image/z/5192436-12-6.jpg?t=%E8%A7%92%CE%B1%E7%9A%84%E7%BB%88%E8%BE%B9%E7%BB%8F%E8%BF%87%E7%82%B9P%28x%2C%EF%BC%8D%E2%88%9A2%29%E4%B8%94cos%CE%B1%3D%28%E2%88%9A3%2F6%29x%E5%88%99sin%CE%B1%2Btan%CE%B1%3D)
角α的终边经过点P(x,-√2)且cosα=(√3/6)x则sinα+tanα=
角α的终边经过点P(x,-√2)且cosα=(√3/6)x则sinα+tanα=
角α的终边经过点P(x,-√2)且cosα=(√3/6)x则sinα+tanα=
角α的终边经过点P(x,-√2)且cosα=(√3/6)x
tanα=-√2/x sina=tanacosa=-√6/6
x=√10或-√10
则sinα+tanα=-√6/6-√2/√10=-√6/6-√5/5
或者-√6/6+√5/5