求函数f(x)=x²/x²-4x+1 x∈【1/3,1】的值域.
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求函数f(x)=x²/x²-4x+1 x∈【1/3,1】的值域.
求函数f(x)=x²/x²-4x+1 x∈【1/3,1】的值域.
求函数f(x)=x²/x²-4x+1 x∈【1/3,1】的值域.
1/f(x)=(x²-4x+1)/x²=1-4/x+1/x²=(1/x-2)²-3
1≤1/x≤3
-3≤1/f(x)≤-2
-1/2≤f(x)≤-1/3