把代数式(a²-2ab+b²+5)(-a²+2ab-b²+5)写成(5+M)(5-M)的形式,并求出M
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![把代数式(a²-2ab+b²+5)(-a²+2ab-b²+5)写成(5+M)(5-M)的形式,并求出M](/uploads/image/z/3816976-40-6.jpg?t=%E6%8A%8A%E4%BB%A3%E6%95%B0%E5%BC%8F%28a%26%23178%3B-2ab%2Bb%26%23178%3B%2B5%29%28-a%26%23178%3B%2B2ab-b%26%23178%3B%2B5%29%E5%86%99%E6%88%90%285%2BM%29%285-M%29%E7%9A%84%E5%BD%A2%E5%BC%8F%2C%E5%B9%B6%E6%B1%82%E5%87%BAM)
把代数式(a²-2ab+b²+5)(-a²+2ab-b²+5)写成(5+M)(5-M)的形式,并求出M
把代数式(a²-2ab+b²+5)(-a²+2ab-b²+5)写成(5+M)(5-M)的形式,并求出M
把代数式(a²-2ab+b²+5)(-a²+2ab-b²+5)写成(5+M)(5-M)的形式,并求出M
(a²-2ab+b²+5)(-a²+2ab-b²+5)
=((a²-2ab+b²)+5)(-(a²-2ab+b²)+5)
=((a-b)2+5)(5-(a-b)2)
=(5+(a-b)2)(5-(a-b)2)
所以M=(a-b)2
有什么不懂的可以再问.O(∩_∩)O~
(a²-2ab+b²+5)(-a²+2ab-b²+5)
=(a²-2ab+b²+5){5-(a²-2ab+b²)}设M=a²-2ab+b²
=(5+M)(5-M)
问题实在不全 看不懂
M=(a-b)²
赞同楼上解法