已知x=(1+√2009)\2,求(4x^2-4x-2007)^2008
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![已知x=(1+√2009)\2,求(4x^2-4x-2007)^2008](/uploads/image/z/3756960-0-0.jpg?t=%E5%B7%B2%E7%9F%A5x%3D%281%2B%E2%88%9A2009%29%5C2%2C%E6%B1%82%284x%5E2-4x-2007%29%5E2008)
已知x=(1+√2009)\2,求(4x^2-4x-2007)^2008
已知x=(1+√2009)\2,求(4x^2-4x-2007)^2008
已知x=(1+√2009)\2,求(4x^2-4x-2007)^2008
=[(2x-1)^2-2008]^2008
=[(1+√2009-1)^2-2008]^2008
=[2009-2008]^2008
=1
1