若X-2Y+6+(X+Y+12)²=0,求4X+ 5Y的值若X-2Y+6的绝对值+(X+Y+12)²=0,求4X+ 5Y
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![若X-2Y+6+(X+Y+12)²=0,求4X+ 5Y的值若X-2Y+6的绝对值+(X+Y+12)²=0,求4X+ 5Y](/uploads/image/z/330262-70-2.jpg?t=%E8%8B%A5X-2Y%2B6%2B%EF%BC%88X%2BY%2B12%EF%BC%89%26%23178%3B%3D0%2C%E6%B1%824X%2B+5Y%E7%9A%84%E5%80%BC%E8%8B%A5X-2Y%2B6%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%2B%EF%BC%88X%2BY%2B12%EF%BC%89%26%23178%3B%3D0%EF%BC%8C%E6%B1%824X%2B+5Y)
若X-2Y+6+(X+Y+12)²=0,求4X+ 5Y的值若X-2Y+6的绝对值+(X+Y+12)²=0,求4X+ 5Y
若X-2Y+6+(X+Y+12)²=0,求4X+ 5Y的值
若X-2Y+6的绝对值+(X+Y+12)²=0,求4X+ 5Y
若X-2Y+6+(X+Y+12)²=0,求4X+ 5Y的值若X-2Y+6的绝对值+(X+Y+12)²=0,求4X+ 5Y
分析:根据绝对值和平方的非负性得,若绝对值+平方=0,则两个式子分别为0.
由题意得,
x-2y+6=0,x+y+12=0,解得,x=-10,y=-2,所以,原式=4×(-10)+5×(-2)=-50