tanπ/12-cotπ/12
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![tanπ/12-cotπ/12](/uploads/image/z/2561603-59-3.jpg?t=tan%CF%80%2F12-cot%CF%80%2F12)
tanπ/12-cotπ/12
tanπ/12-cotπ/12
tanπ/12-cotπ/12
=sinπ/12/cosπ/12-cosπ/12/sinπ/12
=(sin²π/12-cos²π/12)/(sinπ/12cosπ/12)
=-cos(2*π/12)/[1/2*sin(2*π/12)]
=-cosπ/6/(1/2*sinπ/6)
=-2√3
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来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 15:38:36
tanπ/12-cotπ/12
tanπ/12-cotπ/12
tanπ/12-cotπ/12
=sinπ/12/cosπ/12-cosπ/12/sinπ/12
=(sin²π/12-cos²π/12)/(sinπ/12cosπ/12)
=-cos(2*π/12)/[1/2*sin(2*π/12)]
=-cosπ/6/(1/2*sinπ/6)
=-2√3