已知,A/(x+2)+B/(2x-3)=(5x-11)/(2x^2+x-6)求A、B的值
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![已知,A/(x+2)+B/(2x-3)=(5x-11)/(2x^2+x-6)求A、B的值](/uploads/image/z/247641-33-1.jpg?t=%E5%B7%B2%E7%9F%A5%2CA%2F%28x%2B2%29%2BB%2F%282x-3%29%3D%285x-11%29%2F%282x%5E2%2Bx-6%29%E6%B1%82A%E3%80%81B%E7%9A%84%E5%80%BC)
已知,A/(x+2)+B/(2x-3)=(5x-11)/(2x^2+x-6)求A、B的值
已知,A/(x+2)+B/(2x-3)=(5x-11)/(2x^2+x-6)
求A、B的值
已知,A/(x+2)+B/(2x-3)=(5x-11)/(2x^2+x-6)求A、B的值
a(2x-3)/(x+2)(2x-3)+b(x+2)/(x+2)(2x-3)=(5x-11)/(x+2)(2x-3)
[a(2x-3)+b(x+2)]/(x+2)(2x-3)=(5x-11)/(x+2)(2x-3)
a(2x-3)+b(x+2)=5x-11
2ax+bx-3a+2b=5x-11
(2a+b)x+(2b-3a)=5x-11
2a+b=5①
2b-3a=-11②
①×2
4a+2b=10③
③-②
7a=21
a=3
b=-1