(x-3)²-(x-3)=12用因式分解法
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 19:52:21
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(x-3)²-(x-3)=12用因式分解法
(x-3)²-(x-3)=12用因式分解法
(x-3)²-(x-3)=12用因式分解法
(x-3)²-(x-3)=12
(x-3)^2-(x-3)-12=0
[(x-3)-4][(x-3)+3]=0
(x-7)(x)=0
x1=0
x2=7
(x-3)²-(x-3)=12
(x-3)²-(x-3)-12=0
(x-3-4)(x-3+3)=0
x(x-7)=0
x1=0 x2=7
(x-3)²-(x-3)=12
(x-3)²-(x-3)-12=0
(x-3-4)(x-3+3)=0
x(x-7)=0
x1=0 x2=7
设(x-3)=Y 就是说先用换元