log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)

log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)
log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)

log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)
由于函数y=log1/2 x是一个减函数,则有：00
2^x>5
x>log2(5)
综上,解集是log2(5)