x²+y²+4x-2y-4=0则(x-1)²+(y-1)²的最大值
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 05:23:46
![x²+y²+4x-2y-4=0则(x-1)²+(y-1)²的最大值](/uploads/image/z/1636687-55-7.jpg?t=x%26%23178%3B%2By%26%23178%3B%2B4x-2y-4%3D0%E5%88%99%28x-1%29%26%23178%3B%2B%28y-1%29%26%23178%3B%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC)
x²+y²+4x-2y-4=0则(x-1)²+(y-1)²的最大值
x²+y²+4x-2y-4=0则(x-1)²+(y-1)²的最大值
x²+y²+4x-2y-4=0则(x-1)²+(y-1)²的最大值
x²+y²+4x-2y-4=0
(x-1)²+(y-1)²+6x-6=0
(x-1)²+(y-1)²= 6-6x
(x+2)²+(y-1)²=9
这是一个以(-2,1)为中心,半径3的圆,x的取值范围是[-5,1]
所以MAX=36