(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/22 00:26:16
![(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,](/uploads/image/z/15114399-15-9.jpg?t=%28y%2B2%29%28y-2%29%28y-1%29%28y%2B5%29%E5%B9%B3%E6%96%B9%E5%B7%AE%E8%AE%A1%E7%AE%97%E8%BF%87%E7%A8%8B%E8%A6%81%E8%AF%A6%E7%BB%86%2C%E5%B0%A4%E5%85%B6%E6%98%AF%28y-1%29%28y%2B5%29%2C%E5%86%99%E6%B8%85%E6%A5%9A%E4%B8%BA%E4%BB%80%E4%B9%88%E4%BC%9A%E5%BE%97%E5%87%BA%E9%82%A3%E4%B8%AA%E7%BB%93%E6%9E%9C%2C)
(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
(y+2)(y-2)(y-1)(y+5)
= (y+2)(y-2)(y+2-3)(y+2+3)
= (y^2-4){(y+2)^2-3^2}
= (y^2-4){y^2+4y+4-9}
= (y^2-4){(y^2+4)+4y-9}
= (y^2-4)(y^2+4)+4y (y^2-4)-9(y^2-4)
= y^4-16 +4y^3-16y^2 -9y^2+36
= y^4+4y^3-25y^2+20
(Y-1)*(Y+5)=[(Y+2)-3]*[(Y+2)+3]=(Y+2)^2-3^2
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y (3y^2+8y-3)-6y(3y+2y-1)+9y
5y∧2-(y-2)(3y+1)-2(y+1)(y-5)
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)
解方程:3y²-(2y+1)(y-2)=(y-5)(y+1)
2(y-4)(3y+2)-5(-3y+7)(y+1),其中y=-1
(y平方+2y)(y平方+2y+2)+1
方程y''=(1+y'*y')/2y的通解
y-y-1/2=2-y+5/5一元一次方程
1/2y+1=4y-2/5-y
y-(y-1)/2=1-(2y-3)/5
y-y-1/2=3-y+2/5
y-2分之y-1=-5分之y+2
解方程y-[3y-1]等于5【y+2]
y'=1+y^2