若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值
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![若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值](/uploads/image/z/14760768-48-8.jpg?t=%E8%8B%A5f%28x%29%3Dax%26%23179%3B-bx-1%2C%E4%B8%94f%28-2%29%3D8%2C%E6%B1%82f%282%29%E7%9A%84%E5%80%BC)
若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值
若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值
若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值
f(x)=ax³-bx-1,f(x)+1=ax³-bx
f(-2)=8,f(2)+1=-f(-2)-1=-9
f(2)=-10
f(-2)=-8a+2b-1=8
8a-2b=-9
f(2)
=8a-2b-1
=-9-1
=-10
f(x)+1为奇函数
f(-2)+1=9
所以f(2)+1=-9
f(2)=-10