一条倾斜角为135°的直线被两条平行直线x+2y-1=0,x+2y-3=0所截,且所截线段的中点在直线x-y-1=0上,求这条直线的方程.答案是3x+3y-5=0,求高手给过程.
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![一条倾斜角为135°的直线被两条平行直线x+2y-1=0,x+2y-3=0所截,且所截线段的中点在直线x-y-1=0上,求这条直线的方程.答案是3x+3y-5=0,求高手给过程.](/uploads/image/z/14742421-61-1.jpg?t=%E4%B8%80%E6%9D%A1%E5%80%BE%E6%96%9C%E8%A7%92%E4%B8%BA135%C2%B0%E7%9A%84%E7%9B%B4%E7%BA%BF%E8%A2%AB%E4%B8%A4%E6%9D%A1%E5%B9%B3%E8%A1%8C%E7%9B%B4%E7%BA%BFx%2B2y-1%3D0%2Cx%2B2y-3%3D0%E6%89%80%E6%88%AA%2C%E4%B8%94%E6%89%80%E6%88%AA%E7%BA%BF%E6%AE%B5%E7%9A%84%E4%B8%AD%E7%82%B9%E5%9C%A8%E7%9B%B4%E7%BA%BFx-y-1%3D0%E4%B8%8A%2C%E6%B1%82%E8%BF%99%E6%9D%A1%E7%9B%B4%E7%BA%BF%E7%9A%84%E6%96%B9%E7%A8%8B.%E7%AD%94%E6%A1%88%E6%98%AF3x%2B3y-5%3D0%2C%E6%B1%82%E9%AB%98%E6%89%8B%E7%BB%99%E8%BF%87%E7%A8%8B.)
一条倾斜角为135°的直线被两条平行直线x+2y-1=0,x+2y-3=0所截,且所截线段的中点在直线x-y-1=0上,求这条直线的方程.答案是3x+3y-5=0,求高手给过程.
一条倾斜角为135°的直线被两条平行直线x+2y-1=0,x+2y-3=0所截
,且所截线段的中点在直线x-y-1=0上,求这条直线的方程.答案是3x+3y-5=0,求高手给过程.
一条倾斜角为135°的直线被两条平行直线x+2y-1=0,x+2y-3=0所截,且所截线段的中点在直线x-y-1=0上,求这条直线的方程.答案是3x+3y-5=0,求高手给过程.