求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值
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![求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值](/uploads/image/z/142808-32-8.jpg?t=%E6%B1%82%E5%88%86%E5%BC%8F1%EF%BC%8F%EF%BC%88x%26%23178%3B%EF%BC%8Bx%EF%BC%89%2B1%EF%BC%8F%EF%BC%88x%26%23178%3B%2B3x%2B2%EF%BC%89%2B1%EF%BC%8F%EF%BC%88x%26%23178%3B%2B5x%2B6%EF%BC%89%2B1%EF%BC%8F%EF%BC%88x%26%23178%3B%2B7x%2B12%EF%BC%89%2B1%EF%BC%8F%EF%BC%88x%26%23178%3B%2B9x%2B20%EF%BC%89%E7%9A%84%E5%80%BC)
求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值
求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值
求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值
1/(X)(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3)画到这里我有印象了就是1/2+1/6+1/12就是1-1/2+1/2_1/3+1/3-1/4所以这题的答案是1/X-1/(X+5)=5/(X(X+5)