求(1/2001-1)*(1/2000-1)*(1/1999-1)*...*(1/1001-1)*(1/1000-1)的值怎么做?
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![求(1/2001-1)*(1/2000-1)*(1/1999-1)*...*(1/1001-1)*(1/1000-1)的值怎么做?](/uploads/image/z/142724-20-4.jpg?t=%E6%B1%82%EF%BC%881%2F2001-1%EF%BC%89%2A%EF%BC%881%2F2000-1%EF%BC%89%2A%EF%BC%881%2F1999-1%EF%BC%89%2A...%2A%EF%BC%881%2F1001-1%EF%BC%89%2A%EF%BC%881%2F1000-1%EF%BC%89%E7%9A%84%E5%80%BC%E6%80%8E%E4%B9%88%E5%81%9A%3F)
求(1/2001-1)*(1/2000-1)*(1/1999-1)*...*(1/1001-1)*(1/1000-1)的值怎么做?
求(1/2001-1)*(1/2000-1)*(1/1999-1)*...*(1/1001-1)*(1/1000-1)的值怎么做?
求(1/2001-1)*(1/2000-1)*(1/1999-1)*...*(1/1001-1)*(1/1000-1)的值怎么做?
=(-2000/2001)(-1999/2000)(-1998/1999)……(-1000/1001)(-999/1000)
分子从999到2000
所以有2000-998=1002个括号
即有1002个负号相乘,所以结果是正数
前一个括号的分子和后一个括号的分母约分
所以=999/2001=333/667