(1)(a-2b+3c)(a+2b-3c)(2)(2x-3y)^2-(y+3x)(3x-y)(3)(2x+y+z)(y-2x-z)(4)2(a-b)^2-a(a-b)

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(1)(a-2b+3c)(a+2b-3c)(2)(2x-3y)^2-(y+3x)(3x-y)(3)(2x+y+z)(y-2x-z)(4)2(a-b)^2-a(a-b)

(1)(a-2b+3c)(a+2b-3c)(2)(2x-3y)^2-(y+3x)(3x-y)(3)(2x+y+z)(y-2x-z)(4)2(a-b)^2-a(a-b)
(1)(a-2b+3c)(a+2b-3c)(2)(2x-3y)^2-(y+3x)(3x-y)(3)(2x+y+z)(y-2x-z)(4)2(a-b)^2-a(a-b)

(1)(a-2b+3c)(a+2b-3c)(2)(2x-3y)^2-(y+3x)(3x-y)(3)(2x+y+z)(y-2x-z)(4)2(a-b)^2-a(a-b)
(1)(a-2b+3c)(a+2b-3c)
=[a-(2b-3c)][a+(2b-3c)]
=a²-(2b-3c)²
=a²-4b²+12bc-9c²
(2)(2x-3y)^2-(y+3x)(3x-y)
=4x²-12xy+9y²-9x²+y²
=-5x²-12xy+10y²
(3)(2x+y+z)(y-2x-z)
=[y+(2x+z)][y-(2x+z)]
=y²-(2x+z)²
=y²-4x²-4xz-z²
(4)2(a-b)^2-a(a-b)
=2(a²-2ab+b²)-a²+ab
=2a²-4ab+2b²-a²+ab
=a²-3ab+2b²

(a-b+c/a+b-c)-(a-2b+3c/b-c+a)+(b-2c/c-a-b) 已知:(a-b)(b-c)(c-a)/(a+b)(b+c)(c+a)=5/132,求a/(a+b)+b/(b+c)+c/(c+a)的值!(请尽快,我有急用,a/(a+b)+b/(b+c)+c/(c+a)=1/2[(a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a)]+3/2 (a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a) 没有错吧... (a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3 2a(a+b-c)-3b(a+b-c)+5c(c-a-b) a,b,c∈R+,证(a+b+c)(1/a+1/b+1/c)>=9证1.(a+b+c)(1/a+1/b+1/c)>=92.(a+b+c)(1/a+b +1/b+c +1/c+a)>=9/23.a/b+c +b/c+a +c/a+b>=3/2 2a(b-c)+3(c-b) 化简|a-b|-2c-|c+b|+|3b| c 3a-c=4a+2b-c=a+b+c a:b:c (a+b-c)^3*(c-b-a)^2*(a+b-c)^6 等于?) 1/a=2/b=3/c求a+b-c/a-b+c=? A=B+B+B+B+B+B+B+B+B+B+B+B+B+B+B A-B×3=C C+2×7+2=1A=B+B+B+B+B+B+B+B+B+B+B+B+B+B+BA-B×3=CC+2×7+2=148148-(C-32)=DA,B,C,D各是多少? 化简:7(a-b-c)-5(a+b-c)+3(a-b-c)+(a+b-2) (1) 化简 (x-c)/(x-a)(x-b)+(b-c)/(a-b)(x-b)+(b-c)/(b-a)(x-a)(2) 化简(2a-b-c)/(a-b)(a-c)+(2b-c-a)/(b-c)(b-a)+(2c-a-b)/(c-b)(c-a)(3) 证明,若a+b+c=0,则1/(b方+c方-a方)+1/(c方+a方-b方)+1/(a方+b方-c方)=0 5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)] 初中数学题(说明理由)由去括号的法则,可得a-(b+c)=a-b-c,a-(b-c)=a-b+c,a-(-b+c)=a+b-c,所以有a-b-c=a-(b+c),a-b+c=a-(b-c),a+b-c=a-(-b+c).试根据以上规律填空1+2xy-x^2-y^2=1-( )已知a^2-2a=-1,求3 如图,化简:b a 0 c.3|b-a|-|a-2c|+1/2|2b+c|.2|b+b|-|a+c|-1/2|c-b| a^2(b+c)+b^2(a+c)+c^2(a+b)+3abc=0,a^2+b^2+c^2=1求a+b+c 已知a>0,b>0,c>0,求证:(1)(a+b)(b+c)(c+a)>=8abc;(2)(a/b)+(b/c)(c/a)>=3