【紧急】求满足下列条件的函数f(x)的解析式:(1)f(x)为一次函数,且f[f(x)]=4x+4.(2)f(x)为二次函数,且f(x+4)+f(x-1)=x^2-2x
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![【紧急】求满足下列条件的函数f(x)的解析式:(1)f(x)为一次函数,且f[f(x)]=4x+4.(2)f(x)为二次函数,且f(x+4)+f(x-1)=x^2-2x](/uploads/image/z/12322074-66-4.jpg?t=%E3%80%90%E7%B4%A7%E6%80%A5%E3%80%91%E6%B1%82%E6%BB%A1%E8%B6%B3%E4%B8%8B%E5%88%97%E6%9D%A1%E4%BB%B6%E7%9A%84%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%9A%EF%BC%881%EF%BC%89f%28x%29%E4%B8%BA%E4%B8%80%E6%AC%A1%E5%87%BD%E6%95%B0%2C%E4%B8%94f%5Bf%28x%29%5D%3D4x%2B4.%EF%BC%882%EF%BC%89f%28x%29%E4%B8%BA%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%2C%E4%B8%94f%28x%2B4%29%2Bf%28x-1%29%3Dx%5E2-2x)
【紧急】求满足下列条件的函数f(x)的解析式:(1)f(x)为一次函数,且f[f(x)]=4x+4.(2)f(x)为二次函数,且f(x+4)+f(x-1)=x^2-2x
【紧急】求满足下列条件的函数f(x)的解析式:
(1)f(x)为一次函数,且f[f(x)]=4x+4.
(2)f(x)为二次函数,且f(x+4)+f(x-1)=x^2-2x
【紧急】求满足下列条件的函数f(x)的解析式:(1)f(x)为一次函数,且f[f(x)]=4x+4.(2)f(x)为二次函数,且f(x+4)+f(x-1)=x^2-2x
吉米,这样的题不会做?
f(x)为一次函数,那 f(x) = ax +b, a,b待定.
f(f(x)) = a^2*x + ab + b = 4x + 4.
剩下的自己去算吧.