数列{an},a1=1,a(n+1)=c-1/an.c=5/2,bn=1/(an-2)求{bn}的通项公式.1/[a(n+1)-2]=2an/(an-2)下一步怎么写?1/[a(n+1)-2]=4/(an-2)+2所以 b(n+1)=4bn+2都不懂怎么来的
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![数列{an},a1=1,a(n+1)=c-1/an.c=5/2,bn=1/(an-2)求{bn}的通项公式.1/[a(n+1)-2]=2an/(an-2)下一步怎么写?1/[a(n+1)-2]=4/(an-2)+2所以 b(n+1)=4bn+2都不懂怎么来的](/uploads/image/z/119958-6-8.jpg?t=%E6%95%B0%E5%88%97%7Ban%7D%2Ca1%3D1%2Ca%EF%BC%88n%2B1%EF%BC%89%3Dc-1%2Fan.c%3D5%2F2%2Cbn%3D1%2F%EF%BC%88an-2%EF%BC%89%E6%B1%82%7Bbn%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F.1%2F%5Ba%28n%2B1%29-2%5D%3D2an%2F%28an-2%29%E4%B8%8B%E4%B8%80%E6%AD%A5%E6%80%8E%E4%B9%88%E5%86%99%3F1%2F%5Ba%28n%2B1%29-2%5D%3D4%2F%28an-2%29%2B2%E6%89%80%E4%BB%A5+b%28n%2B1%29%3D4bn%2B2%E9%83%BD%E4%B8%8D%E6%87%82%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84)
数列{an},a1=1,a(n+1)=c-1/an.c=5/2,bn=1/(an-2)求{bn}的通项公式.1/[a(n+1)-2]=2an/(an-2)下一步怎么写?1/[a(n+1)-2]=4/(an-2)+2所以 b(n+1)=4bn+2都不懂怎么来的
数列{an},a1=1,a(n+1)=c-1/an.c=5/2,bn=1/(an-2)求{bn}的通项公式.1/[a(n+1)-2]=2an/(an-2)下一步怎么写?
1/[a(n+1)-2]=4/(an-2)+2
所以 b(n+1)=4bn+2都不懂怎么来的
数列{an},a1=1,a(n+1)=c-1/an.c=5/2,bn=1/(an-2)求{bn}的通项公式.1/[a(n+1)-2]=2an/(an-2)下一步怎么写?1/[a(n+1)-2]=4/(an-2)+2所以 b(n+1)=4bn+2都不懂怎么来的
1/[a(n+1)-2]=2an/(an-2)
=(2an-4+4)/(an-2)
=2+4/(an-2)
所以b(n+1)=2+4bn
b(n+1)+2/3=4(bn+2/3).
{bn+2/3}是等比数列.
看看明白不?不明白追问
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